What would be the radius of the capillary tube so that water
will rise to a height of 8 cm in it?
Answers
Answered by
0
Answer:
r =1.785*10 p0wer -4m
Explanation:
h=2T/rpg
r=2T/hpg
T=surface tension of water=70*10 power-3 N/m
r=2*70*10 power-3 N/mdivided by 8*10 power -2 *10 power 4
=1.785*10 p0wer -4m
Similar questions