Question

What would be the radius of the capillary tube so that water
will rise to a height of 8 cm in it?​

Answer 1

Answer:

r =1.785*10 p0wer -4m

Explanation:

h=2T/rpg

r=2T/hpg

T=surface tension of water=70*10 power-3 N/m

r=2*70*10 power-3 N/mdivided by 8*10 power -2 *10 power 4

 =1.785*10 p0wer -4m