Question

What would be the remainder when the sum of a 2 digits no. And the no. Obtained by reversing its digits is divided by 11?

Answer 1

Answer:0

Step-by-step explanation:num=10x+y

Rev. num=10y+x

Sum=10x+y+10y+x=11y+11x

When you divide it by 11,quotient is x+y and it divides completely leaving the rem. 0

Answer 2

Answer:

Let two digits number be 10x+y

Now,sum of the number and number reversing by its digit,

10x+y+10y+x=11(x+y)

which is divisible by 11

hence reminder is zero.

Ans.0