What would be the result if the number that shyam thought was 7/4and the number given by ram was 3/2. Does ram’s trick still work? Maths
Answers
not sure about the answer
Complete Question :- Ram and syam were playing a game and krithi who is 1 year younger than ram was watching them play. Here is their conversation.Ram: shyam, think of a number in your mind and then double it.(Shyam told the number to krithi and the number was 5)Ram: add 6 to the result and then find the half of the number.Shyam did the calculation and got the result as (5+5+6)/2= 8.Ram : then subtract the number that you thought in the starting from the result, 3 is left behind.Krithi was so surprised by this and asked ram how did he get to know, he told her that he is a magician and started laughing.
What would be the result if the number that shyam thought was 7/4and the number given by ram was 3/2. Does ram’s trick still work ?
Solution :-
Let us assume that, shyam think of number in mind is x .
so,
→ Double of number = 2x
now,
→ Add 6 to the number and half = (2x + 6)/2
now, subtracting the number , result is 3 .
→ (2x + 6)/2 - x = 3
hence, the required algebraic expression representing this situation is (2x + 6)/2 - x = 3 .
The result if the number that shyam thought was 4 is,
→ (2 * 4 + 6)/2 - 4
→ (8 + 6)/2 - 4
→ (14/2) - 4
→ 7 - 4
→ 3 .
now, the result if the number that shyam thought was 7/4and the number given by ram was 3/2.
→ (2 * 7/4 + 6)/2 - 7/4 = 3/2
→ (7/2 + 6)/2 - 7/4 = 3/2
→ (7 + 12)/2 - 7/4 = 3/2
→ (19/2) - (7/4) = (3/2)
→ (19*2 - 7)/4 = (3/2)
→ (31/4) ≠ (3/2)
therefore, required result is (31/4) and ram's trick doesnt work .
The result if the number that shyam thought was (-4) is,
→ (2 * -4 + 6)/2 - (-4)
→ (-8 + 6)/2 + 4
→ (-2/2) + 4
→ (-1) + 4
→ 3 .
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