What would be the tension in the string if I apply a force of 10 Newton from one side and 60 Newton on the other. The string is massless.
Answers
Answer:Solution
a)
The free body diagram below shows the weight W and the tension T1 acting on the block. Tension T2 acting on the ceiling and Fc the reaction to T2.
forces and tension in a suspended box
Hence action reaction (Newton's 3 rd law) : |Fc| = |T2|
We now consider the forces acting on the block (Free Body Diagram)
Since the block is at rest W + T1 = 0 (Newton's second law, vector equation)
W = (0 , -|W|)
T1 = (0, |T1|)
Hence : (0 , -|W|) + (0, |T1|) = 0
sum of y coordinates = 0 gives |W| = |T1|
T1 and T2 represent the tension of the string and their magnitudes are equal. Hence
|T2| = |T1|
T2 and Fc are action and reaction pairs and therefore their magnitudes are equal. Hence
|Fc| = |T2| = |T1| = |W| = m g = 5×10 = 50 N
Explanation:
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