What would be the total current flowing through the following circuit?
Answers
Answer:
given that - R1 = 2 ohm
R2 = 4 ohm
R3 = 4 ohm
R4 = 6 ohm
V = 12 volt..
from above fig we came to knew that R2 and R3 are in parallel so by parallel combination...
1 / Req* = 1 / R2 + 1 / R3
1 / Req* = 1 / 4 + 1 / 4 = 2 / 4 = 1 / 2
Req* = 2 ohm
then ...R1 and Req* and R4 are in series so by series combination....
Rnet = R1 + Req* + R4 = 2 + 2 + 6 = 10 ohm..
by ohms law we came to knew that ,
V = I X R
Inet = V / R = 12 / 10 = 1.2 A
Total current flowing in the circuit is 1.2 A
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Answer:
Explanation: Total resistance=2+2+6=10ohm
Voltage= 12V
Total Current= Voltage/Resistance
=12/10=1.2 A