what would be the value of acceleration due to gravity of a planet of mass (3*10power24 ) kg and radius (3.2*10power6) m
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Answer:
6.7×10^-22×3.2^-2
Step-by-step explanation:
- we know that,
- g =G × M/ r^2.
- g = 6.7 × 10^ -11 × 3 × 10 ^24/ 3.2 ×10^6 × 3.2 × 10 ^6.
- g= 6.7 × 10^-22×3.2^-2
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