Question

What would be the value of 'g' on earths surface if its mass was twice -and its radium half of what it is now? mass of earth = 6*10^24; radius =6.4*10^6. please try to explain this sum in detail by solving it on your book by sending phoTO​

Answer 1

Answer:

g= G *M/R^2

______________

g'= G * M'/R'^2

g'=G*2M/R^2/4

_______________

g= G*M/R^2

g'=8g