What would be the value of g on the surface of earth if the mass of earth is doubled and its radius is half of what it is now? (The mass of earth is 6*10²⁴ kg, and radius of earth is 6.4*10raise to the power 6)
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8 times the actual value of g
ssm121:
But can you explain me properly
GM/r^2 =g
M=MASS OF earth
G =GRAVITATIONAL CONSTANT
r=radius of earth
hope u understand
Yes but what is the connection of mass doubled and radius made half with this
put M=2M and r=r/2 in the formula i mentioned
Oh thanks
welcome
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