what would be the value of 'g' on the surface of the earth if its mass was twice and its radius
half of what it is now?
Answers
Answered by
1
Answer:
g =2 G M /r
Explanation:
Answered by
5
Answer:
g1=78.4m/s²
Explanation:
As we Know the formula :
g= GM/R²----------------(1)
where g is acceleration due to gravity
M is mass of the earth
R is radius of earth
G is universal gravitational constant.
If mass is twice =2M
RADIUS is half= R/2
let g1 be the new gravity .
Substituting in formula (1) we get.
g1= Gx2M/(R/2)²
g1=8 (GM/R²)
g1= 8xg
So the new gravity would be 8 times of original value that is 9.8 m/s².
Hence g1=78.4m/s²
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