Question

what would be the value of g on the surface of the earth if its mass was twice as large and its radius half of what it is now?​

Answer 1

see the attached image, that may help you.

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Answer 2

Explanation:

g=(GMe)÷Radius of earth^2

New g

(G2Me)÷[{(Re)÷2}]^2

g=8[(GMe)÷(Radius of earth)^2]

new g=8× old g

So the new g is 8 times of the old value of g. Therefore the value of new g is 9.8×8=78.4m/s^2