Question

What would be the value of ‘g’ on the surface of the earth if its mass

was twice and its radius half of what it is now?​

Answer 1

Answer:

Earth's gravitational acceleration , g=GMR2

g1=GM1R21andg2=GM2R23

g2g1=(M2M1)(R1R2)2=2(2)2=8

g2=8g1 Thus , the value of g on the surface of the earth would be eight times the present value.

Answer 2

Explanation:

hope it helps you!!!

please mark me as brainlist!!