Question

what would be the value of g on the surface of the Earth if its mass was twice as large and its radius half of what it is now ?

Answer 1

Hey there,

g=GM/r^2

Now ,g(new)=G(2M)/(r/2)^2
= GM/r^2 ×8=8g.

Hence, it will b'come 8 times of

present g and u are going to get

crushed on this new gravity.

Hope it helps

Answer 2

Answer:

gm/r^2(8)=8g

Explanation:

because itits twice in eg mean 8