what would be the value of g on the surface of the Earth if its mass was twice as large and its radius half of what it is now ?
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Answered by
78
Hey there,
g=GM/r^2
Now ,g(new)=G(2M)/(r/2)^2
= GM/r^2 ×8=8g.
Hence, it will b'come 8 times of
present g and u are going to get
crushed on this new gravity.
Hope it helps
g=GM/r^2
Now ,g(new)=G(2M)/(r/2)^2
= GM/r^2 ×8=8g.
Hence, it will b'come 8 times of
present g and u are going to get
crushed on this new gravity.
Hope it helps
yamuna16:
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Answered by
2
Answer:
gm/r^2(8)=8g
Explanation:
because itits twice in eg mean 8
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