what would be the value of g on the surface of the earth if the mass wSs twice as large and its radius is half
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If we take mass 'm'
and Radius 'r'
Now by the given conditions
mass= 2(m)
radius =r/2
and
by the universal law of gravitation
F=GMm/r^2
that is
F is force of gravity .
so.F=2m/(r/2)^2
=4×2m/r^2
=8m/r^2
and Radius 'r'
Now by the given conditions
mass= 2(m)
radius =r/2
and
by the universal law of gravitation
F=GMm/r^2
that is
F is force of gravity .
so.F=2m/(r/2)^2
=4×2m/r^2
=8m/r^2
prasad113:
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