What would be the value of n^(sq) - 1 divisible by 8. [n^(2)= n power 2 ]
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n² - 1 is divisible by 8,
So (n² - 1) is a multiple of 8.
n²-1= 8k
n² = 8k + 1
n =(8k+1)^(1/2)
Where k is an integer
If n if an integer and range of n is given, then find n by putting different values of k for which (8k+1) is a perfect square
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