what would be the velocity of the ball falling freely from 10 M height when it touches the ground (g=9.8ms2)
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Convention: up and right +ve and left and down -ve
note the bell is in free fall
hence u(initial velocity) =0m/s ,a = -9.8m/s² s (displacement)
using the kinematic equation v²-u²=2as
v²=2×-9.8m/s × 10m
⇒v²=196 m²/s²
⇒v=√(196 m²/s²)
⇒v=+ or - 14m/s
We get 2 answers but what math tells us is the ball is here dispalcement is 10m and acceleration is g and the final velocity is + or - 14m/s .; both of them satisfy the equation . We are asked about the case where it is downward . In this case the final velocity is 14m/s downward.
I hope that helps!
note the bell is in free fall
hence u(initial velocity) =0m/s ,a = -9.8m/s² s (displacement)
using the kinematic equation v²-u²=2as
v²=2×-9.8m/s × 10m
⇒v²=196 m²/s²
⇒v=√(196 m²/s²)
⇒v=+ or - 14m/s
We get 2 answers but what math tells us is the ball is here dispalcement is 10m and acceleration is g and the final velocity is + or - 14m/s .; both of them satisfy the equation . We are asked about the case where it is downward . In this case the final velocity is 14m/s downward.
I hope that helps!
Wimpybrain:
it is the ball by the way ; a small typing error
in the sixth line it is 2 times-9.8m/s/s times -10m
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