Question

what would be the volume in liters of 85.5 g of carbon monoxide at stp

Answer 1

Answer:

The volume of 85.5g of CO at STP is 68.4L.

Explanation:

Given,

          mass of CO = 85.5g

molar mass of CO = 28g/mol.

   moles of CO = mass of CO / molar mass of CO

⇒                       = 85.5/28 = 3.05 moles

       1 mole of a gas occupies 22.4L at STP.

Thus, 3.05 moles of CO occupy 3.05 × 22.4L at STP.

Hence, the volume of CO is 68.4L at STP.