Question

what would be the volume of a block twice as long twice as wide and twice as high as the metal block in the first part​

Answer 1

Answer:

Step-by-step explanation:

As the mass of P is twice that of Q.

Density = M/V

Density of P (d P) = 2M/V

Density of Q (d Q)= M/V

So, d P/d Q = 2M/M = 2.

d P = 2 d Q, so density of P is twice that of Q which option is not given.

Now, Energy = mass (m) * specific heat capacity (s) * temperature (t).

Energy of P = 2*m*sP*t

Energy of Q = m*sQ*t

Since, the energies are equal, 2*m*sP*t = m*sQ*t

sP / sQ = m / 2m (as t is also same)

That is, sP / sQ = 1 / 2. Therefore, sP = 1/2 sQ.

Hence, the specific heat capacity of P is half that of Q.