what would be the volume of water displaced by a 500g sealed tin of volume 350^3 when fully dipped into lure water??
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Mass of packet = 500 g
Volume of packet = 350 cm3
Density of packet = Mass ÷ Volume = (500 ÷ 350) g/cm3 = 1.43 g/cm3
The sealed packet will sink in the water as its density is more tan that of water.
The volume of water that will be displaced by the packet = 350 cm3
And mass of this displaced water = Volume x Density = 350 x 1 = 350 gm
HOPING IT WILL BE HELPFUL
Volume of packet = 350 cm3
Density of packet = Mass ÷ Volume = (500 ÷ 350) g/cm3 = 1.43 g/cm3
The sealed packet will sink in the water as its density is more tan that of water.
The volume of water that will be displaced by the packet = 350 cm3
And mass of this displaced water = Volume x Density = 350 x 1 = 350 gm
HOPING IT WILL BE HELPFUL
apurv5:
it's a question of S.chand publication book
you r in class -10th ???
no in 9
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