what would be the work done on the system if the internal energy of the system falls by100 j even when 200 joules of heat is suplied to it
Answers
Answered by
1
Answer:
W= Q - ∆U
Q = 200 & ∆U = -100
W = 200 - (-100)
W = 300 J
Answered by
1
Answer:
dQ = du + dw,
=> 200 = -100 + dw,
=> dw = 300 joules.
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