Question

what would be the work done on the system if the internal energy of the system falls by100 j even when 200 joules of heat is suplied to it

Answer 1

Answer:

We have to calculate the work done on/by the system if the internal energy of the system falls by 100 joules even when 200 joules of heat is supplied to it.

Solution:

By sign convention,

dQ = du + dw  .......... (1)

du = 200 J  ( ∵Heat absorbed is positive )

dw = - 100 J   ( ∵Heat given out is negative )

Substitute these values in (1):

dQ = 200 - (-100)

dQ = 200 + 100

dQ = 300 J

This is the required answer.