what would be volume of water displaced by 500g sealed tin of volume 350cm³ when completely dipped in pure water?
bunny175:
don't k know
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350 cm3 as the tin is submerged completely in water. Here is the calculation:
Density of the tin = (Mass of the tin) / (Volume of the tin) = (500 / 350) g /cm3 = 1.428 g /cm3
As the density of tin is more than water, it will completely sink.
Since the tin will remain completely submerged,
Mass of water displaced by the tin will be = (volume of tin * density of water) = (350 cm3 * 1 g/cm3) = 350 g.
Density of the tin = (Mass of the tin) / (Volume of the tin) = (500 / 350) g /cm3 = 1.428 g /cm3
As the density of tin is more than water, it will completely sink.
Since the tin will remain completely submerged,
Mass of water displaced by the tin will be = (volume of tin * density of water) = (350 cm3 * 1 g/cm3) = 350 g.
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