What would happened to the resistor of a wire if it is stretched to double its length? Justify your answer?
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As the length L becomes 2times ,the cross sectional area A will be halved when we stretch it because before and after stretching the volume will be same.Now as the resistance is directly proportional to the length of a conductor and inversely proportional to the cross sectional area, putting the value of length 2L and area A/2 in the formula for calculating resistance we will find that the resistance has now become 4 times the original resistance.Initially R=ρL/A now R'=ρ2L/A÷2=4ρL/A=4R.Hope it helps.
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