Question

What would the entropy change be for this process?

H2O(g) → H2O(l)

Answer 1

Answer:

The process, H2O(l)⇌H2O(g), is an endothermic process, (△H=+ve) and entropy increases during this change (△S=+ve). Hence this process is spontaneous at all temperatures above 0∘C(T△S>△H, so △G is negative △G=△H−T△S).