Question

what would the value of g on the surface of the earth if it mass was twice as large and its radius half of what its is now​

Answer 1

Explanation:

g= GM/R²----------------(1)

g= GM/R²----------------(1)where g is acceleration due to gravity

g= GM/R²----------------(1)where g is acceleration due to gravity.

g= GM/R²----------------(1)where g is acceleration due to gravity.If mass is twice =2MRADIUS is half= R/2let g1 be the new gravity .Substituting in formula (1) we get.g1= Gx2M/(R/2)²g1=8 (GM/R²)g1= 8xgSo the new gravity would be 8 times of original value that is 9.8 m/s².Hence g1=78.4m/s²