Question

what would you observe when you put some aluminium pieces in copper sulphate solution

Answer 1

What happens is this:

2Al + 3CuSO4•5H2O = Al2(SO4)3•6H2O + 3Cu + 9H2O(l)

Change in Free Energy: ΔG(20C) = -1309.1kJ (negative, so the reaction runs)

Change in Enthalpy: ΔH(20C) = -1241.1kJ (negative, so the reaction is exothermic)

You would notice that the copper was precipitated out of solution, and that the characteristic blue color of the copper sulfate disappeared, and the solution was colorless.
Hope you understand.......
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Answer 2

Answer:

ok.. thanks for ur answer buddy