English, asked by saki3447, 15 days ago

What you normally do on sundays

Answers

Answered by princerauniyar05
0

Answer:

wasting most of time of my life

Explanation:

hope you also... n

Answered by deepak1463
4

Explanation:

♣ Given: −

An object is dropped from rest from a height of 100 m .

Simultaneously another object is dropped from rest from a height of 50 m.

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\large \clubs \:  \bf To \: Find :  -♣ ToFind: −

Difference in their heights after 2 s.

How does the difference in heights vary with time ?

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\large \clubs \:  \bf Solution :  -♣ Solution: −

Here Acceleration is the Acceleration due to gravity (g).

Acceleration = a = g = 10 m/s²

We Have 2nd Equation of Kinematics as :

\red \bigstar \: \boxed{\orange{ \boxed{ \bf{s =ut} + \dfrac{1}{2}{at}^{2}}}}★s=ut+21at2

★ For First Body :-

Time = t = 2 second

Initial Velocity = u = 0 m/s

Acceleration = a = 10 m/s²

✏ Using 2nd Equation of Kinematics :

★ Distance covered by 1st body :

\begin{gathered} \text s_1 = 0 + \frac{1}{2} \times 10 \times {2}^{2} \\ \end{gathered}s1=0+21×10×22

\purple{ \large :\longmapsto  \underline {\boxed{{\bf s_1 = 20 \: m} }}}:⟼  s1=20m

As Initial Height first body is 100 m

Hence,

Height of 1st body after 2s = 100 - 20

⇝Height of 1st body after 2s = 80 m

Now,

★ For Second Body :-

Time = t = 2 second

Initial Velocity = u = 0 m/s

Acceleration = a = 10 m/s²

✏ Using 2nd Equation of Kinematics :

★ Distance covered by 2nd body :

\begin{gathered} \text s_2 = 0 + \frac{1}{2} \times 10 \times {2}^{2} \\ \end{gathered}s2=0+21×10×22

\purple{ \large :\longmapsto  \underline {\boxed{{\bf s_2 = 20 \: m} }}}:⟼  s2=20m

As Initial Height Second body is 50 m

Hence,

Height of 2nd body after 2s = 50 - 20

⇝Height of 2nd body after 2s = 30 m

So,

Difference in their Heights after 2s = 80 - 30

\begin{gathered}\underline{\bf \pink{\underline{Difference \: in \: their \: Heights}}}\\ \underline{\bf \pink{\underline{after \: 2s = 50 m }}}\end{gathered}DifferenceintheirHeightsafter2s=50m

Also,

It concluded that initial difference between their Heights is equals to final difference between their Heights

So,

\begin{gathered}\underline{\bf \pink{\underline{Difference\: in\: their\: Heights}}}\\ \underline{\bf \pink{\underline{ does\: not\: vary\: with\: time}}}\end{gathered}DifferenceintheirHeightsdoesnotvarywithtime

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