What you normally do on sundays
Answers
Answer:
wasting most of time of my life
Explanation:
hope you also... n
Explanation:
♣ Given: −
An object is dropped from rest from a height of 100 m .
Simultaneously another object is dropped from rest from a height of 50 m.
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\large \clubs \: \bf To \: Find : -♣ ToFind: −
Difference in their heights after 2 s.
How does the difference in heights vary with time ?
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\large \clubs \: \bf Solution : -♣ Solution: −
Here Acceleration is the Acceleration due to gravity (g).
Acceleration = a = g = 10 m/s²
We Have 2nd Equation of Kinematics as :
\red \bigstar \: \boxed{\orange{ \boxed{ \bf{s =ut} + \dfrac{1}{2}{at}^{2}}}}★s=ut+21at2
★ For First Body :-
Time = t = 2 second
Initial Velocity = u = 0 m/s
Acceleration = a = 10 m/s²
✏ Using 2nd Equation of Kinematics :
★ Distance covered by 1st body :
\begin{gathered} \text s_1 = 0 + \frac{1}{2} \times 10 \times {2}^{2} \\ \end{gathered}s1=0+21×10×22
\purple{ \large :\longmapsto \underline {\boxed{{\bf s_1 = 20 \: m} }}}:⟼ s1=20m
As Initial Height first body is 100 m
Hence,
Height of 1st body after 2s = 100 - 20
⇝Height of 1st body after 2s = 80 m
Now,
★ For Second Body :-
Time = t = 2 second
Initial Velocity = u = 0 m/s
Acceleration = a = 10 m/s²
✏ Using 2nd Equation of Kinematics :
★ Distance covered by 2nd body :
\begin{gathered} \text s_2 = 0 + \frac{1}{2} \times 10 \times {2}^{2} \\ \end{gathered}s2=0+21×10×22
\purple{ \large :\longmapsto \underline {\boxed{{\bf s_2 = 20 \: m} }}}:⟼ s2=20m
As Initial Height Second body is 50 m
Hence,
Height of 2nd body after 2s = 50 - 20
⇝Height of 2nd body after 2s = 30 m
So,
Difference in their Heights after 2s = 80 - 30
\begin{gathered}\underline{\bf \pink{\underline{Difference \: in \: their \: Heights}}}\\ \underline{\bf \pink{\underline{after \: 2s = 50 m }}}\end{gathered}DifferenceintheirHeightsafter2s=50m
Also,
It concluded that initial difference between their Heights is equals to final difference between their Heights
So,
\begin{gathered}\underline{\bf \pink{\underline{Difference\: in\: their\: Heights}}}\\ \underline{\bf \pink{\underline{ does\: not\: vary\: with\: time}}}\end{gathered}DifferenceintheirHeightsdoesnotvarywithtime
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