Question

Whatbis the answer of X^2-4y^2=41

Answer 1

${x}^{2} - 4 {y}^{2} = 41$

${(x)}^{2} - {(2y)}^{2} = 41$

$by \: \: \: {a}^{2} - {b}^{2} = (a + b)(a - b)$

$(x + 2y)(x - 2y) = 41$

Answer 2

Answer:

${x}^{2} - (2y) {}^{2} = 41$

$(x + 2y)(x - 2y) = 41 \times 1 = (21 + 2 \times 10)(21 - 2 \times 10)$

so X = 21 & Y = 10

Ans.

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