Question

whatis the kinetic energy of50gm bullet moving at a speed of 500 ms-1​

Answer 1

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• K. E. =
• $\frac{1}{2} \times \frac{1}{20} \times 500 \times 500$
• $= 6250$

Answer 2

Answer:

Explanation:

m=50g

=50/ 1000 kg

m=0.05 kg

v=500 m/s

Kinetic Energy = 1/2mv²

=  1/2× 0.05 × 500 × 500

= 6250 J