Chemistry, asked by deukewte, 3 months ago

whats the answer of this plz help​

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Answered by mamtasagar1981
4

(b) is the correct option, frequency of this light is 5*10¹⁴s-1

Answered by saquib2603
7

Answer:

E=12400/lambda

E=hv

v=E/h

v=12400/6.6×10^-34lambda

v=1.878×10^-31/600×10^-9

v=0.00313×10^-22

v=3.13×10^-19

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