Question

whats the equation of the line that passes through the points (2,-5) and has a slope of -4

Answer 1

Step-by-step explanation:

(y - y1) = m (x - x1)

y - y1) = m (x - x1)given slope m = -4

y - y1) = m (x - x1)given slope m = -4 (x1 , y1) = (2,-5)

y - y1) = m (x - x1)given slope m = -4 (x1 , y1) = (2,-5)(y + 5) = -4(x - 2)

y - y1) = m (x - x1)given slope m = -4 (x1 , y1) = (2,-5)(y + 5) = -4(x - 2)y + 5 = -4x +8

y - y1) = m (x - x1)given slope m = -4 (x1 , y1) = (2,-5)(y + 5) = -4(x - 2)y + 5 = -4x +84x + y -3 =0

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