Question

whats the volume of co2 liberated at stp by heating 1g of caco3

Answer 1

Explanation:

• CaCO3 ----> CaO + CO2

From above equation 1 mole (100g) gives 1 mole (44g) CO2

So, 1 g CaCO3 gives 0.44 g of CO2

$moles \: = \frac{given \: mass}{molar \: mass}$

$moles \: = \frac{0.44}{44}$

$moles \: = 0.01$

$mole s\: = \frac{volume}{22.4}$

$volume \: = moles \: \times \: 22.4$

$volume \: = 0.01 \times 22.4$

$volume \: = 0.224 \: litres$