Question

whay is the smallest number that when divided by 35,56,91 leaves remainder 7 in each case ​

Answer 1

Answer:it's 91

Step-by-step explanation:because it not decisive and it will leave the remainder and 35 and 56 are divisible 35 is divisible by 5 and 56 by 2 and 91 is not divisible by any number exempt 1

Answer 2

Answer:

LCM(35,56,91)= 3640

so, 3640+7=3647

So, "3647" is the number that when divided by 35,56,and 91 leaves remainder 7 in each case.