Wheels of diameters 7 cm and 14 cm start rolling simultaneously from ends X and Y
which are 1980 cm apart, towards each other in opposite directions. Both of them
make same number of revolutions per second. If both of them meet after 10 seconds,
then find the speed of the smaller wheel.
Answers
Answered by
26
Answer: 22m/s
Explanation:
let each wheel make x revolutions per sec. Then[(2π*72*x)+(2π*7*x)]*10=1980(2*227*72*x)+(2*227*72*x)=198
66x=198
distance moved by smaller wheel in 3 revolutions
=2*227*72*3=66cm
speed of smaller wheel = 663 m/s = 22m/s
Answered by
1
Answer:
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Explanation:
let each wheel make x revolutions per sec. Then[(2π*72*x)+(2π*7*x)]*10=1980(2*227*72*x)+(2*227*72*x)=198
66x=198
distance moved by smaller wheel in 3 revolutions
=2*227*72*3=66cm
speed of smaller wheel = 663 m/s = 22m/s
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