Question

When 0.03 L of a mixture of hydrogen and oxygen
was exploded, 0.003 L of oxygen remained. The
initial mixture contains (by volume)
(a) 60% O2
(b) 40% O2
(c) 50% O2
(d) 30% O2

Answer 1

Answer:

According to the following equation....

2 mol H2 reacts with 1 mol O2.

Let us assume that volume of H2 in the mixture = 2x L

So the volume of O2 in the mixture must be = (x +0.003)L

Then we get the equation..

2x +x+0.003= 0.02

or

x= 0.0056 L

Thus volume of H2 in mixture= x=0.0112L

and

volume of O2 in mixture = x+0.003=0.008L

so

Composition of O2 =(0.008/0.02) x 100= 40%

and

Composition of H2= (0.012/0.02) X 100 = 60%

hope it helps...!!

Answer 2

Answer:

Your correct answer is a 60 % O2