Question

.
When 0.1 ml of0.1 N HCl is added to 100 ml of
pure water the pH of the solution will be​

Answer 1

Answer:

Explanation:

Since NaCl is a salt that is neutral in nature so it will not effect the pH of solution,

So, H+ =N1V1 / Vsolution = 0.2 × 10−3 / 0.1 + 100 = 0.2 x 10-3 / 1.001 = 0.1998

M ≈ 0.2 M

pH=−log[H+]=−log(0.2)=0.699 ≈ 0.70

I hope you understand.