Question

When 0.1 mol CoCl₃ (NH₃)₅ is treated with excess of AgNO₃,
0.2 mol of AgCl are obtained. The conductivity of solution
will correspond to
(a) 1 : 3 electrolyte (b) 1 : 2 electrolyte
(c) 1 : 1 electrolyte (d) 3 : 1 electrolyte

Answer 1

The conductivity of solution  will correspond to 1:2 electrolyte.

Option (B) is correct.

Explanation:

One mole of AgNO3 precipitates one mole of chloride ion.

In the given reaction, when 0.1 mole CoCl3(NH3)5Cl]Cl2 and electrolytic solution must contain [Co(NH3)5Cl]2+ and two Cl− as constituent ions.

Thus it is 1:2 electrolyte.

[Co(NH3)5Cl]Cl2 → [Co(NH3)5Cl]2 + aq + 2Cl− aq

Hence the conductivity of solution  will correspond to 1 : 2 electrolyte.

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Conductivity of a solution containing 1 gram of anhydrous BaCl2 in centimetre cube what has been found to be 0.0058 7 centimetre inverse what are the molar conductance and equivalent conductance of the solution (if weight of Ba =137 and cl=35.5​  ?

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