Chemistry, asked by devidnath673, 1 year ago

When 0.1 mol Mno4^(-2)is oxidised the quantity of
electricity required to completely oxidise MnO4^(-2) to
Mno4^-, is
[AIPMT-2014]
(1) 96500 C (2) 2 x 96500 C
(3) 9650 C
(4) 96.50 C​

Answers

Answered by Anonymous
20

{\sf MnO_4^{-2}⇋MnO_4^{-}+e^{-} }

Here ,

Oxidation State of \sf{MnO_4^{-2}} is +6 and Oxidation State of \sf{MnO_4^{-}} is +7.

We can see that ,

for 1 mole of \sf{MnO_4^-} , 1F of electricity is required.

•°• for 0.1 mole of

\implies{\sf 1F = 96500}

\implies{\sf 0.1F=0.1×96500}

\implies{\sf 9650\:C}

\Large\underline{\underline{\sf \blue{Answer}:}}

•°• For 0.1 mole 9650 C electricity require to oxidise \underline{\sf MnO_4^{-2}} to \underline{\sf MnO_4^{-}}

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