Question

When 0.1 mol MnO₄²⁻ is oxidised the quantity of electricity
required to completely oxidise MnO₄²⁻ to MnO₄⁻ is:
(a) 96500 C (b) 2 × 96500 C [2014]
(c) 9650 C (d) 96.50 C

Answer 1

answer : option (c) 9650 C

here, MnO₄²⁻ ⇒MnO₄⁻ + e⁻

if we ejects one electron from one molecule of MnO₄²⁻, it gives one molecule of MnO₄⁻.

so, we should remove 0.1 mol of electrons from 0.1 mol of MnO₄²⁻ to get 0.1 mol of MnO₄⁻.

from Faraday law, 1 mol of electron is equivalent to 96500 C

so, 0.1 mol of electrons is equivalent to 96500 × 0.1 = 9650 C

hence, option (c) 9650 C is correct choice.

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