Physics, asked by pratappradeep031, 2 months ago

When 0.15 kg of ice at 0 °C is mixed with 0.3 kg of water at 50 °C in a container. The resulting

temperature is 6.7 °C. calculate the latent heat of fusion of ice. Given: Sw = 4186 J kg -1K

-1​

Answers

Answered by ankitachatterjee3747
0

Explanation:

When 0.15kg of ice at 0

o

C is mixed with 0.30kg of water at 50

o

C in a container, the resulting temperature is 6.7

o

C. Calculate latent heat of melting of ice.

(Specific heat of water is 4.186×10

3

JKg

−1

).

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