When 0.1M of HCI is reacted with 0.2M of NaOh, it from NaOh . What will be the concentration of NaOh?
Give NaOh=2ml
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Explanation:
Using M1V1 = M2V2 We have
0.1 × V1. = 0.2 × 2
V1 = 0.4/0.1 = 4ml
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