Question

when 0.24g of magnesium is reacted with excess HCL what volume of gas is liberated at RTP
a)120cm3
b)240cm3
c)360cm3
d)3600cm3​
(with solution)​

Answer 1

Mg+ 2 HCl =========> MgCl2 + H2.

Atomic weight of Mg= 24.

So 24- g of Mg will liberate 22.4 Litres of Hydrogen gas at STP.

So 0.24g of Mg will liberate =22.4x0.24/24= 0.224- Litres of Hydrogen gas at STP.( Or)

224 ml of Hydrogen gas at STP. ============================

At rtp the volume of 1- mole a gas= 24- Litres.

So volume of 0.01- mole a gas at rtp will occupy= 0.01 x 24= 0.240- litres (or) 240 - ml.

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