Question

when 0.273 g of m is heated strongly in N2 gas atmosphere, a chemical reaction occur. The product of reaction weigh 0.378g .What is the empirical formula of the compound? (M= 24)

Answer 1

0.273 g of M is heated strongly in N2 gas and forms 0.378g of compound.

then, amount of Nitrogen in compound = 0.378g - 0.273g = 0.105g

then, mass % of nitrogen in compound = 0.105g/0.378g × 100 = 27.77%

mass % of M in compound = 0.273/0.378 × 100 = 72.23%

Let the mass of chemical compound is 100g

then, mass of M = 72.23g

and mass of N = 27.77g

now, mole of M in compound = 72.23/24 ≈ 3 [ as molecular weight of M = 24g/mol ]

mole of N in compound = 27.73/14 ≈ 2

here it is clear that 3 mole of M and 2 mole of N combine to form chemical compound so, empirical formula of compound is M3N2