Question

When 0.440 mol of aluminum are allowed to react with an excess of chlorine gas, Cl2, how manymoles of aluminum chloride are produced? 5)A) 0.880 mol B) 0.220 mol C) 0.330 mol D) 0.110 mol E) 0.440 mol

Answer 1

Answer:

When 0.440 mol of aluminum are allowed to react with an excess of chlorine gas, Cl2, how manymoles of aluminum chloride are produced? 5)A) 0.880 mol B) 0.220 mol C) 0.330 mol D) 0.110 mol E) 0.440 mol

Explanation:

When 0.440 mol of aluminum are allowed to react with an excess of chlorine gas, Cl2, how manymoles of aluminum chloride are produced? 5)A) 0.880 mol B) 0.220 mol C) 0.330 mol D) 0.110 mol E) 0.440 molWhen 0.440 mol of aluminum are allowed to react with an excess of chlorine gas, Cl2, how manymoles of aluminum chloride are produced? 5)A) 0.880 mol B) 0.220 mol C) 0.330 mol D) 0.110 mol E) 0.440 molWhen 0.440 mol of aluminum are allowed to react with an excess of chlorine gas, Cl2, how manymoles of aluminum chloride are produced? 5)A) 0.880 mol B) 0.220 mol C) 0.330 mol D) 0.110 mol E) 0.440 mol

Answer 2

Given - Moles of aluminium - 0.440

Find - Moles of aluminium chloride formed.

Solution - Reaction of aluminium and chloride will be as follows -

2Al + 3Cl2 --> 2AlCl3

In the reaction, Al is aluminium, Cl is chlorine and AlCl3 is aluminium chloride.

In presence of excess chlorine gas, aluminium will be the limiting reagent. As 2 moles of aluminium give 2 moles of aluminium chloride, 0.440 moles of aluminium will produce 0.440 moles of aluminium chloride.

Hence, option E) 0.440 mol is the correct answer.