Question

When 0.45 Kg of ice at 0oc is mixed with 0.9 Kg of water at 55oC in a container , the resulting temp is 10.0oC . Calculate the heat of fusion of ice ?

Answer 1

Given:

When 0.45 Kg of ice at 0°c is mixed with 0.9 Kg of water at 55°C in a container , the resulting temp is 10.0°C .

To find:

Heat of fusion of ice?

Calculation:

Let latent heat of fusion of ice be L :

• All mass values to be put in grams.

Applying Principle of CALORIMETRY:

$\therefore \: heat \: released \: by \: water = heat \: taken \: up \: by \: ice$

$\implies \: (m1)c(\Delta \theta_{1}) = (m2)L + (m2)c(\Delta \theta_{2})$

$\implies \: (900) \times 1 \times (55 - 10) = (450)L + (450) \times 1 \times (10 - 0)$

$\implies \: (900) \times 1 \times (45) = (450)L + (450) \times 1 \times (10 )$

$\implies \:40500= (450)L + 4500$

$\implies \:(450)L = 40500 - 4500$

$\implies \:(450)L = 36000$

$\implies \:L =80 \: Cal/g$

So, latent heat of fusion is 80 Cal/gram.

Answer 2

Answer:

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