Question

When 0.5 a is passed is passed through acidulated water for 2 hours?

Answer 1

At cathode,

2H+ + 2e → H2

Equation of H2=i.t/96500

=0.5×2×60×60/96500

=0.037

Volume of H2=22.4×0.0372/2 litre

=0.4

Answer :0.4litre