When 0.7 L of Hydrogen at 0.8 bar and 1.5 L of Oxygen at 0.6 bar are introduced in a 1 L vessel at
25°C, the total pressure of the gas mixture is.....??
Answers
Answered by
22
Heya.....!!!!
As we know that ,, Total pressure of the gas mixture = P1V1 + P2V2 ÷ V
=> P1 = 0.7
=> V1 = 0.8
=> P2 = 1.5
=> V2 = 0.6
Then Total pressure = P1V1 + P2V2/V
Here , V = 1
Putting the values We get
➡ ( 0.7×0.8 ) + ( 1.5×0.6 ) ÷ 1
Final answer ➡➡ 1.46 bar
Total pressure => 1.46 bar .
Hope it helps u ^_^
As we know that ,, Total pressure of the gas mixture = P1V1 + P2V2 ÷ V
=> P1 = 0.7
=> V1 = 0.8
=> P2 = 1.5
=> V2 = 0.6
Then Total pressure = P1V1 + P2V2/V
Here , V = 1
Putting the values We get
➡ ( 0.7×0.8 ) + ( 1.5×0.6 ) ÷ 1
Final answer ➡➡ 1.46 bar
Total pressure => 1.46 bar .
Hope it helps u ^_^
Answered by
0
Answer:
As we know that ,, Total pressure of the gas mixture = P1V1 + P2V2 ÷ V
=> P1 = 0.7
=> V1 = 0.8
=> P2 = 1.5
=> V2 = 0.6
Then Total pressure = P1V1 + P2V2/V
Here , V = 1
Putting the values We get
➡ ( 0.7×0.8 ) + ( 1.5×0.6 ) ÷ 1
Final answer ➡➡ 1.46 bar
Total pressure => 1.46 bar .
FOLLOW ME
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