When 0.833g of hydrated salt (X. nH20) was heated to dryness, 0.533g of anhydrous salt of molar mass 160 was formed. What is the number of water molecules per formula weight of the hydrate?
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Answer:
250
Explanation:
the molecular weight of X is 160 g and the experiment yielded 0.533 g of Xn when 0.833 g of XnH2O was heated.
moles of X = 0.533/160 = 0.00333 mole
Mass of nH2o = 0.833 - 0.533 = 0.300 g H2O
molar mass of H2O = 18.0 g/mole
0.300 / 18.0 = 0.0167 mole H2O
moles of H2O / moles of X = 0.0166 / 0.00333 = 5.0
X.5H2O
Formula weight of X.5H2O = 160 + 5x18.0 = 160 + 90 = 250
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