Question

When 0 # nt, n e Z, then
sino
1 + cose
sine
+
sino 1-cos
is equal to
1 + cos
Ꮎ
(1) 2 cos?
(2) 2 sin2
ON
2
0
0
(3) sin + COS
2 2
(4) sin
singo
a
- COS-
2 2​

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

Answer:

Given that sinθ+cosθ=1

now squaring both side we have

(sinθ+cosθ)2=12

sin2θ+cos2θ+2sinθcosθ=1

1+2sinθcosθ=1                   (sin2θ+cos2θ=1)

2sinθcosθ=0

sin2θ=0           (sin2θ=2sinθcosθ)