Question

When 1 contains 3 red and 4 black balls and another bag contains 5 red and 6 black balls one ball is drawn at random from black bag 1 and without noticing its colour it is put into the back to then?

Answer 1

Answer:

Step-by-step explanation

3red 4black in bag 1

5 red 6black In bag 2

So one ball is drawn randomly

So n(A)=1

n(S)=7 in bag 1

So P(A)=n(A)/n(S)

P(A)=1/7