Math, asked by 1968rameshmv, 1 month ago

When 1 is added to each of two numbers their ratio becomes 1:2and when 5 is subtracted from each of them ,their ratio is 5:11.The difference of the numbers is​

Answers

Answered by tennetiraj86
1

Step-by-step explanation:

Given :-

When 1 is added to each of two numbers their ratio becomes 1:2and when 5 is subtracted from each of them ,their ratio is 5:11

To find :-

Find the difference of the numbers?

Solution :-

Let the required numbers be X and Y

If 1 is added to the numbers then they becomes

(X+1) and (Y+1)

Their ratio = (X+1):(Y+1)

Given that

When 1 is added to each of two numbers their ratio becomes 1:2

=> (X+1):(Y+1) = 1:2

=> (X+1)/ (Y+1) = 1/2

On applying cross multiplication then

=> 2(X+1) = 1(Y+1)

=> 2X+2 = Y+1

=> Y+1 = 2X+2

=> Y = 2X+2-1

=> Y = 2X+1 -------------(1)

If 5 is subtracted from each of them they becomes (X-5) and (Y-5)

Their ratio = (X-5):(Y-5)

Given that

when 5 is subtracted from each of them ,their ratio is 5:11.

=> (X-5):(Y-5) = 5:11

=> (X-5)/(Y-5) = 5/11

On applying cross multiplication then

=> 11(X-5) = 5(Y-5)

=> 11X-55 = 5Y-25

=> 11X-5Y = -25+55

=> 11X-5Y = 30 --------(2)

On Substituting the value of Y in (2) ,from (1)

=> 11X -5(2X+1) = 30

=> 11X -10X-5 = 30

=> X -5 = 30

=> X = 30+5

=> X = 35

On Substituting the value of X in (1)

=> Y = 2(35)+1

=> Y = 70+1

=> Y = 71

The value of X = 35

The value of Y = 71

The difference of the numbers

= 71-35

= 36

Answer:-

The difference of the given numbers is 36

Check :-

X = 35 and Y = 71

When 1 is added to each of two numbers their ratio becomes 1:2

=> (35+1):(71+1)

=> 36:72

=> 1:2

when 5 is subtracted from each of them ,their ratio is 5:11

=>(35-5):(71-5)

=> 30:66

=> 5:11

Verified the given relations in the given problem

Used Method :-

  • Substitution method

Answered by snehasingh1012006
0

Step-by-step explanation:

Let the no.s be x and y.

given, A/Q,

x+1:y+1=1:2

y+1

x+1

=

2

1

2x+2=y+1

2x−y=−1 (1)

Again, x−5:y−5=5:11

y−5

x−5

=

11

5

11x−55=5y−25

11x−5y=30 (2)

from 1 and 2, by elimination method,

(1)×5⇒10x−5y=−5

(2)×1⇒11x−5y=30

−1x=−35,so,x=35

We know, from (1)

2x−y=−1

putting x==35, we get

2×35+1=y

71=y

so the no are 30 and 71.

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hope this help you

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